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5] FD1-> {student,language guide FD2-> {guide)-> language
For the above functional dependencies, give appropriate reasons if it is in BCNF form or not?
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5] FD1-> {student,language guide FD2-> {guide)-> languageFor the above...
Explanation:

1. Decomposition into FD1 and FD2:
- FD1: {student, language guide}
- FD2: {guide} -> {language}

2. Checking for BCNF:
- A relation is in BCNF if for every non-trivial functional dependency X -> Y, X is a superkey.

3. Analysis:
- FD1: {student, language guide}
- {student} is not a superkey as {student} does not uniquely determine all attributes in the relation.
- Violation of BCNF as {student} is not a superkey.
- FD2: {guide} -> {language}
- {guide} is a superkey as it uniquely determines {language}.
- Satisfies BCNF as {guide} is a superkey.

4. Conclusion:
- The given functional dependencies are not in BCNF form.
- FD1 violates BCNF as {student} is not a superkey.
- FD2 satisfies BCNF as {guide} is a superkey.
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5] FD1-> {student,language guide FD2-> {guide)-> languageFor the above functional dependencies, give appropriate reasons if it is in BCNF form or not?
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